Tuesday, July 14, 2009

Arranging a number?

Six numbers are arranged in a sequence. the numbers have to be sorted in an ascending order. any step in the rearrangement involves exchanging positions of any two numbers simultaneously. what is the minimum possible number of steps needed to arrange the numbers. if they are initially not in an ascending order ?





a)1


b)3


c)4


d)6





how do isolve ?





should i take random numbers 3,4,1,5,9,0 ? like this ?


whats the easy way to find out the correct option ?

Arranging a number?
one... because four of the numbers could already be in their correct order... only having to do one switch..





ex. 102489 only one switch the 0 and the one... so one is the minimum... now the maximum is a bit more complicated... tell me if you need to know how.. write me sylviakopec@yahoo.com
Reply:try combinations or arangements or permutations
Reply:The least is 1. By making just one exchange it may be possible to sort the numbers in ascending order
Reply:i dont know the answer but i feel 4 you
Reply:The min. no. of steps is 1


while the max. is 5.
Reply:correct answer is (c) you get it easily by gueesing it quickly thats the best way try it out definetely u score above 80% corect answers

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