Here is what is given:Colorblindness is any abnormality of the color vision system that causes a person to see colors differently than most people or to have difficulty distinguishing among certain colors (www.visionrx.xom).
Colorblindness is gender-based with the majority of sufferers being males.
Roughly 8% of white males have some form of colorblindness, while the incidence among white females is only 1%.
A random sample of 20 white males and 40 white females was chosen.
Let X be the number of males (out of the 20) who are colorblind.
Let Y be the number of females (out of the 40) who are colorblind.
Let Z be the total number of colorblind individuals in the sample (males and females together).
Answers:
(a) .4
(b) 1.6
(c) 2
(d) 2.7
(e) The mean of Z cannot be determined.
Hint: Express Z in terms of X and Y and then apply rules for means.
What is the mean of Z, the expected total number of individuals (males and females) who are colorblind?
The answer is (c)
Let X be a random variable with mean μx and variance σx². Let a, and b be constants.
Let W = aX + b
The mean of W, E(W) = μw is:
E(W) = E(aX + b)
= E(aX) + b
= aE(X) + b
in this case we have Z = X + Y
E(X) = 20 * 0.08 = 1.6
E(Y) = 0.4
E(Z) = 1.6 + 0.4 = 2.0
Reply:Since it affects 8% of white males (X), and 1% of white females (Y), then the average number of people (Z), both genders, that are infected will be
Z = 0.08X + 0.01Y
Z = 0.08(20) + 0.01(40)
Z = 2
I would have to say c is the answer.
Hope that helps!!!!!!
Reply:The expectation should just be the weight(probability) multiply by the amount of people.
Mean of X is : (.08*20)
Mean of Y is : (.01*40)
Mean of Z is the addition of the mean of Y and the mean of X
μ_z = μ_x + μ_y
μ_z = (.08*20) + (.01*40) = 2
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment