C++ Basic arrays and pointers question: The Tortoise and the Hare?

Start each animal at square 1 of 70 squares (each square represents possible position. Use variables to keep track of position and if animals slip before square 1 then move them back to square one. Generate %age's by using a random number generator in the range of 1%26lt;= i %26lt;= 10.


Tortoise: Fast plod 1%26lt;= i %26lt;= 5 moves 3 squares right


Slip 6%26lt;= i %26lt;=7 moves 6 squares left


Slow Plod 8%26lt;= i %26lt;=10 moves 1 square right


Hare: sleep 1%26lt;= i%26lt;= 2 no move


Big Hop 3%26lt;= i%26lt;= 4 9 squares right


small hop 5%26lt;= i %26lt;=7 1 square right


Big Slip i == 8 12 squares left


small slip 9%26lt;= i%26lt;=10 2 squares left


Need to print a 70 position line on each loop showing position T (Tortoise), H (Hare). If both land on same square print "OUCH" at that position. all print position should be blank except for T, H and ouch. After each loop test if either animal %26gt;=70 if so print winner and end

C++ Basic arrays and pointers question: The Tortoise and the Hare?
Hmmmm, is this homework? Looks like you want someone to make this for you. How about you attempt it, then ask for help if you get stuck.





If you have no idea how to attempt it, I suggest you study the very basics, or ask your teacher.